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Iterative implementation of the Euclidean algorithm using the remainder operator:

int gcd(int m, int n) { while (m != n) { if (m < n) { n -= m; } else { m -= n; } } return n; } // INVARIANT: gcd(m,n)

X l ( k )= X2(k) =

then Therefore, the N-point circular convolution of x l ( n ) with s z ( n ) is the inverse DFT of X ( k ) , which is

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int gcd(int m, int n) { while (n > 0) { // INVARIANT: gcd(m,n) int r = m%n; m = n; n = r; } return m; }

CHAP. 9]

x(n) =

In general, circular convolution is not the same as linear convolution. However, there is a simple relationship between circular and linear convolution that illustrates what steps must be taken in order to ensure that they are the same. Specifically, let x ( n ) and h ( n ) be finite-length sequences and let y ( n ) be the linear convolution

To prove that the recursive implementation of the Fibonacci function is correct, first verify the basis. The calls fib(0) and fib(1) return the correct values 0 and 1 because of the first line

Recursive implementation of the Euclidean algorithm using the remainder operator:

y(n) =x(n)* h(n)

if (n < 2) { return n; }

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The N-point circular convolution of x ( n ) with h ( n ) is related to y ( n ) as follows:

int gcd(int m, int n) { if (m == 0) { return n; } else if (n == 0) { return m; } else if (m < n) { return gcd(m, n%m); } else { return gcd(m%n, n); } } // basis // basis // recursion // recursion

23 1

Next, we assume that the function returns the correct value for all integers less than some n > 1. Then the second line

In other words, the circular convolution of two sequences is found by performing the linear convolution and

Iterative implementation of the Euclidean algorithm using the remainder operator:

An important property that follows from Eq. (6.10) is that if y ( n ) is of length N or less, y ( n - k N ) # Oand h(n)@ x(n) = h(n)* x(n)

return fib(n-1) + fib(n-2);

int gcd(int m, int n) { while (n > 0) { // INVARIANT: gcd(m,n) int r = m%n; m = n; n = r; } return m; }

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that is, circular convolution is equivalent to linear convolution. Thus, if h ( n ) and x ( n ) are finite-length sequences oflength NI and N 2 , respectively, y ( n ) = h ( n ) * x ( n ) is of length N I Nr - I, and the N -point circularconvolution is equivalent to linear convolution provided N 2 N I N 2 - 1 .

EXAMPLE 6.4.3 Let us find the four-point circular convolution of the sequences h(n) and x ( n ) in Example 6.4.1. Because the linear convolution is

will return the correct value because (by the inductive hypothesis) the calls fib(n-1) and fib(n-2) return the correct values for Fn 1 and Fn 2, respectively, and Fn = Fn 1 + Fn 2 by definition Note that the basis here requires the verification of the first two steps in the sequence because the recurrence relation Fn = Fn 1 + Fn 2 applies only for n > 1 921 If n = 1, then the basis executes, returning a[0] which is the maximum element because it is the only element If n > 1, then the function correctly computes the maximum m of the first n 1 elements (by the inductive hypothesis) If the condition (a[n-1] > m) is true, then that element a[n-1] is returned, and it is the largest because it is larger than m, which is larger than all the others.

To prove that the recursive implementation of the Fibonacci function is correct, first verify the basis. The calls fib(0) and fib(1) return the correct values 0 and 1 because of the first line

y(n) = 6(n)

+ S(n - I ) + 2S(n - 2) + 26(n - 3) + 3S(n - 5)

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