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Our second problem, that of the user closing the pixel data dialog by hand, is more problematic. Since this dialog is a nonmodal window, this dialog can be closed at any time. So we need a mechanism for notifying our main window whenever the dialog is closed. If you recall, and as shown in step 5 in the previous table, the MainForm form is defined as the owner of the PixelDlg form. This ensures that both windows are

I know, I know. There is no such word as unpushed. You know what I mean. I thought about the word released, but unpushed seems much more packed with meaning.

CAUTION:

shown when either window is displayed or minimized. We can take advantage of this relationship to ensure that our main window is notified when the pixel dialog is closed. The trick is to force the MainForm window to activate whenever the PixelDlg dialog is closed. Our main form will then receive an Activated event, at which time we can update our button. Since the MainForm class derives directly from Form, we can handle this event by overriding the protected OnActivated method. The following steps implement this mechanism.

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UPDATE THE TOGGLE BUTTON WHEN THE PIXELDLG FORM IS CLOSED Action 6 In the PixelDlg.cs code window, override the OnClosing method to activate the owner of the dialog, if any. Note: Since the dialog may not be fully closed here if the MainForm.OnActivated method runs immediately, we set the Visible property to false to ensure the correct behavior occurs. Also note that overriding the OnClosed method instead does not work because the Owner property is no longer valid once the dialog has been closed. 7 Back in the MainForm.cs code window, override the OnActivated method. If the pixel dialog does not exist, then make sure our button is not pushed down. Result

To begin with, let s convert to metric units, rounding off to keep the numbers relatively simple 180 lb is 800 N The fact that the player is 6 ft tall is irrelevant (at least to us, perhaps not to the coach) Eight inches is 02 m And 450 lb of force is 2000 N In a real-life situation, the force applied would not be constant However, to keep things simple we can use the average force and assume a constant force (equal to the average force) during the time the basketball player is accelerating up from the bent-knee position Recall that force equals mass times acceleration (F 5 ma), so a constant force means a constant acceleration And a constant acceleration means that the velocity is increasing linearly (in a straight line) This last point is helpful, because it means that wherever we have a constant acceleration, instead of having to figure out the increasing velocity at each point in time, we can simply take the average of the initial and final velocity, and apply that average velocity over the same period of time and get the same mathematical result We break the problem up into the same steps as previously The first step is to determine maximum velocity at the end of step 1 Then using this as the starting velocity of step 2 and applying the downward acceleration of gravity, we calculate the distance traveled until the velocity is zero: This is the height of the jump Before we solve the problem, let s review and derive some basic formulas of motion By definition, speed or velocity is the distance traveled divided by time See Eq (12-1) This will be used to relate the velocity of the jump to the height of the jump (Throughout this section we will use speed and velocity interchangeably, Strictly speaking, velocity and acceleration are vectors, and speed is scalar But for our purposes we are only dealing with motion in the up and down direction Therefore to keep things simple, we will treat velocity and acceleration as scalars and use positive value for the up direction and negative value for the down direction) v 5 d /t (12-1).

protected override void OnClosing (CancelEventArgs e) { Visible = false; if (this.Owner != null) Owner.Activate(); base.OnClosing(e); }

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