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relationship between the two query subjects in the diagram, you will save time if you do the following things: Make sure your query items are showing in the diagram (choose Diagram | Diagram Settings, and then select Query Items under Level of Detail); and drag from the query item in the query subject on the one side of the relationship to the related query item in the query subject on the many side of the relationship If you create the relationship by selecting the query items and choosing Create Relationship from the context menu, select the query item on the one side of the relationship first Framework Manager assumes that you are creating a one-to-many relationship, and it further assumes that the item you click first is on the one side of that relationship It also assumes that the query items you clicked will be the items that define the relationship So, just by clicking the right place, you should have most of your relationships defined correctly for you

For an AHRS application in which position and velocity information are in not available, n = 0 In this case, eqn (1046) is mechanized as b Rn = Rn b b ib (1052)

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Following a method similar to that of Section 10521, to derive the dynamic model for P, set the derivative of eqn (1032) equal to the left side of eqn (1046): PRn + (I + P)Rn b b which simpli es as follows, PRn + (I + P)Rn b b = (I + P)Rn ( b b + b ) in ib b ib n b n = (I + P)Rb + (I + P)Rb ib Rn b b in b b n n b b P = Rb ib Rn Rb in Rn (1054) = (I + P)Rn ( b b ) ib in b (1053)

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What about the 01 and 0n cardinality settings Let s review the difference between inner joins and outer joins When you join information from two query subjects by creating a relationship, you specify the join criteria; that is, you define which field or fields in one query subject should match which field or fields in the other query subject An inner join is characterized by requiring that the information exists in both tables in order for it to be part of the result Inner joins will use only the 11 and 1n cardinalities An outer join says that the information should still be returned if it exists in one of the query subjects even if it does not have a match in the other Outer joins are useful when the absence of information is itself informative For instance, if you have a query subject of Employee information and another that returns Employee Reviews, you might not have a review in your query subject results for every employee From a report perspective, it would be nice to know which employees have not been reviewed, as well as knowing the reviews that some employees have received By specifying an outer join as a relationship with 11 cardinality on the Employee side and 0n cardinality on the Employee Review side, when you report employee review information you will always get the full list of employees and their related review information, if any exist While it might seem beneficial always to model relationships using outer joins, be forewarned that execution of outer joins is usually less efficient than the execution of comparable inner joins Sometimes it is much less efficient Before you model something as

to rst order In vector form (using eqns (223) and (B15)), eqn (1054) is (1055) = Rn b n b ib in where b is the error in the gyro measurement of the body-frame inertialib ib relative angular rate vector By its de nition as b = b b , the ib ib

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