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Known Quantities: Nameplate data Find: = N1 /N2 ; I1 ; I2 Schematics, Diagrams, Circuits, and Given Data: Nameplate data: 120 V/480 V;

Natural selection is de ned by differential reproductive success. Depending upon which phenotypes are most t, natural selection can act in several ways to change allelic and genotypic frequencies. Selection against the recessive homozygote acts to remove the allele from the population. Mutation brings the allele back into the population. Thus, a selection-mutation equilibrium maintains the unfavorable allele at a relatively low frequency. Heterozygote advantage maintains both alleles in a population.

(Contd)

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Assumptions: Assume an ideal transformer Analysis: The rst element in the nameplate data is a pair of voltages, indicating the

ability of its xation is 0.75 (see g. 20.8). Since it is convenient to measure time (number of generations) within populations of nite size in units of population size, we can see that an event that takes N generations will be one thousand generations in the small population, but one million generations in the large population.Thus, random genetic drift occurs in the larger population at about onethousandth the rate of the small population.

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primary and secondary voltages for which the transformer is rated The ratio, , is found as follows: N1 480 = =4 = N2 120 To nd the primary and secondary currents, we use the kVA rating (apparent power) of the transformer: |S| 48 kVA |S| 48 kVA = 100 A I2 = = 400 A = = I1 = V1 480 V V2 120 V

in the transformer; in fact, there will be losses due to coil resistance and magnetic core effects These losses result in heating of the transformer, and limit its rated performance

PROBLEM 3: In a laboratory colony of fruit ies, the t-

Find the equivalent load impedance seen by the voltage source (ie, re ected from secondary to primary) for the transformer of Figure 1635

Table 710 (Contd)

Assumptions: Assume an ideal transformer Analysis: By de nition, the load impedance is equal to the ratio of secondary phasor

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and b. The mutation rate of B to b is 3.5 10 4, whereas the mutation rate of b to B is 6 10 8. What is the equilibrium frequency of the b allele, assuming no other factor is operating in this population to disturb the HardyWeinberg equilibrium Answer: We let q f(b), 3.5 10 4, and 6 8 10 . We then simply substitute and into equation 20.6:

where the ratio V1 /I1 is the impedance seen by the source at the primary coil, that is, the re ected load impedance seen by the primary (source) side of the circuit Thus, we can write the load impedance, Z2 , in terms of the primary circuit voltage and current; we call this the re ected impedance, Z2 : Z2 = 1 V1 1 1 = 2 Z1 = 2 Z 2 2 I 1

( ) (3.5 10 0.9998

Thus, Z2 = 2 Z 2 Figure 1636 depicts the equivalent circuit with the load impedance re ected back to the primary

circuit elements can be referred to a single set of variable (ie, only primary or secondary voltages and currents)

3.5 10 4 4 6 10 8 )

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169 The high-voltage side of a transformer has 500 turns, and the low-voltage side has 100 turns When the transformer is connected as a step-down transformer, the load current is 12 A Calculate: (a) the turns ratio ; (b) the primary current 1610 Calculate the turns ratio if the transformer in Check Your Understanding 169 is used as a step-up transformer 1611 The output of a transformer under certain conditions is 12 kW The copper losses are 189 W and the core losses are 52 W Calculate the ef ciency of this transformer 1612 The output impedance of a servo ampli er is 250 The servomotor that the ampli er must drive has an impedance of 25 Calculate the turns ratio of the transformer required to match these impedances

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