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g(n) is noncausal. Furthermore, because time-reversing a sequence does not affect its absolute summability,

public static void main(String[] args) { for (int n=0; n<10; n++) { System.out.println("f("+n+") = "+f(n)); } }

0 1 2 3 4 5 6 7 8 9

modulating h(n) by (- I)":

The factorial function is also easy to implement iteratively:

Therefore, if h(n) is causal and stable, so is g(t7).

1 1 2 6 24 120 720 5,040 40,310 362,880

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and there are two possible regions of convergence: Izl > 2 and lzl < 2. Because both of these overlap with the region of convergence for H(z), both are valid inverse systems. For J z J 2, the unit sample response is >

1 2 3 4 5 6 7

which is a causal but unstable system. For (zl < 2, the unit sample response is ~ ( n= -2"u(-n )

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This is a recursive definition because the factorial recurs on the right side of the equation. The function is defined in terms of itself. The first 10 values of the factorial function are shown in Table 9.1. The first value, 0!, is defined by the upper half of the definition: 0! = 1 (for n = 0). All the rest of the values are defined by the lower half of the definition: For n = 1, 1! = n! = n(n 1)! = 1(1 1)! = 1(0)! = 1(1) = 1. For n = 2, 2! = n! = n(n 1)! = 2(2 1)! = 2(1)! = 2(1) = 2. For n = 3, 3! = n! = n(n 1)! = 3(3 1)! = 3(2)! = 3(2) = 6. For n = 4, 4! = n! = n(n 1)! = 4(4 1)! = 4(3)! = 4(6) = 24. For n = 5, 5! = n! = n(n 1)! = 5(5 1)! = 5(4)! = 5(24) = 120. Notice how rapidly this function grows.

+ 0.6(2)"-'u(-n)

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public static int f(int n) { int f = 1; for (int i = 2; i <= n; i++) { f *= i; } return f; }

is both stable and causal, and the magnitude of the frequency response is the same as that of the inverse system. Therefore, this system is realizable, and the system that is the cascade of H ( z ) with G ( z )has a frequency response with a magnitude of I .

When a function is defined recursively, its implementation is usually a direct translation of its recursive definition. The two parts of the recursive definition of the factorial function translate directly into two Java statements:

(a) Make a pole-zero plot of the system function, and use geometric arguments to show that if r the system is a notch filter.

Note that the function header is identical to that used in Example 9.2; only the body is different. This allows us to use the same test driver for both implementations. The output should be the same.

and a pair of complex poles just inside ( a ) This system has a pair of complex zeros on the unit circle at z = A pole-zero diagram for H ( z ) is shown in the figure below. the unit circle at z =

1 2 3 4

The first thing to note is that, due to the zeros that are on the unit circle, the frequency response goes to zero at w = i~wo. The second thing to observe is that, as we move away from the unit circle zeros, the lengths of the vectors from the poles to the unit circle approach the lengths of the vectors from the zeros to the unit circle. Furthermore, the closer r is to I , the more rapidly the lengths of these vectors become the same. Therefore, if r 1, H(e1") is a notchfilter, with a frequency response that is approximately constant except within a narrow band of frequencies around w = fwo, where the frequency response goes to zero.

BASIS AND RECURSIVE PARTS To work correctly, every recursive function must have a basis and a recursive part. The basis is what stops the recursion. The recursive part is where the function calls itself. EXAMPLE 9.4 The Basis and Recursive Parts of the Factorial Function

(17)

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