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( b ) Sampling speech at 8 kHz produces 8000 samples per second. Therefore, we have T, = 1/8000 = 0.125 ms to compute each output. This allows for M = (0.125 x 10-"/10-' = 1250 instruction cycles. Thus, we may implement an FIR filter of order N = 1250 - I 1 = 1239.

CHAP. 1]

Find the unit sample response, h(n), of the network drawn below and find the 64-point DFT of h(n).

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while (parser.hasMoreTokens()) { String word = parser.nextToken().toUpperCase(); String frequency = (String)map.get(word); if (frequency==null) { frequency = "1"; } else { int n=Integer.parseInt(frequency); ++n; frequency = "" + n; } map.put(word, frequency); // insert lines 21-40 from Example 8.9

This is a frequency sampling structure for an FIR filter with a unit sample response of length N = 64. Because the gain of the first-order section with a pole at z = I is equal to 1, H(0) = I. With second-order networks of the form

7 8 9 10 11

A(k) = H (k) B(k) =

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A recursive function is one that calls itself. This powerful technique produces repetition without using loops (e.g., while loops or for loops). Thus it can produce substantial results from very little code. Recursion allows elegantly simple solutions to difficult problems. But it can also be misused, producing inefficient code. Recursive code is usually produced from recursive algorithms. SIMPLE RECURSIVE FUNCTIONS EXAMPLE 9.1 The Factorial Function

- k)

public String getName() { return new String(name); } }

we see that H(1) and H(2) are nonzero, along with H(62) and H(63). We may therefore solve these equations for H(1), H(2), H(62), and H(63) as follows. Because A(I) = 2,

0 1 2 3 4 5 6 7 8 9

and because B(1) = 2cos(rc/32),

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18

Thus, we have two equations in two unknowns, which may be written in matrix form as follows:

1 1 2 6 24 120 720 5,040 40,310 362,880

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Solving these equations we find that H(1) = H(63) = 1. Similarly, with A(2) = 2 and B(2) = 2cos(n/32), we find that H(2) = H(62) = 1. Therefore, the 64-point DFT of h(n) is

public class Professor extends Person { public static enum Rank {INSTR, ASST, ASSOC, PROF} private Rank rank; public Professor(String name, Rank rank) { super(name); this.rank = rank; } public Rank getRank() { return rank; } public void setRank(Rank rank) { this.rank = rank; } }

H(k) =

This is a recursive definition because the factorial recurs on the right side of the equation. The function is defined in terms of itself. The first 10 values of the factorial function are shown in Table 9.1. The first value, 0!, is defined by the upper half of the definition: 0! = 1 (for n = 0). All the rest of the values are defined by the lower half of the definition: For n = 1, 1! = n! = n(n 1)! = 1(1 1)! = 1(0)! = 1(1) = 1. For n = 2, 2! = n! = n(n 1)! = 2(2 1)! = 2(1)! = 2(1) = 2. For n = 3, 3! = n! = n(n 1)! = 3(3 1)! = 3(2)! = 3(2) = 6. For n = 4, 4! = n! = n(n 1)! = 4(4 1)! = 4(3)! = 4(6) = 24. For n = 5, 5! = n! = n(n 1)! = 5(5 1)! = 5(4)! = 5(24) = 120. Notice how rapidly this function grows.

k = 0. I . 2, 62.63

The Professor class extends the Person class, inheriting its name field and its getName method. It defines at line 2 an enum field named Rank that specifies the four values INSTR, ASST, ASSOC, and PROF. Its constructor at line 6 requires the professor s name and rank. Note how the Professor constructor uses the super keyword to invoke the Person constructor at line 7.

h(') =

CHAP. 1]

H(k) eJ2nt1"lh -

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27

, + & cos nrr + & cos nrr ,

7 8 9 10 11

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