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The output b from the OPT101 positive inverter circuit would replace the phototransistor input to the RX pin on the MAX3100 If more power is needed on the transmit side, it can be driven by a power transistor or a more capable current source The red LED D1 and the pushbutton S3, shown in the circuit connected to the RTS\output and CTS/input signal lines on the MAX3100, are for test purposes only, as illustrated in the program below The MAX3100 has additional desirable features One of these is a buffer that can hold up to eight received characters until the STAMP gets around to reading them out Another feature is a sleep mode, with automatic wake-up on detection of a start bit (Note that the MAX3100 operates in noninverted mode, with a logical 1, or mark, state being a high level.

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not be expressed as a simple analytical function, then the numerical method is the only recourse to obtain the system response. The differential equation of motion of a system can be expressed in the form = f(x,x ,t) x or x = y = F1(x,y,t) y = f(x, ,t) = F2(x,y,t) x x0 = x(0) x 0 = x (0) (31.56)

where x0 and x 0 are the initial displacement and velocity of the system, respectively. The form of the equation is the same whether the system is linear or nonlinear. Choose a small time interval h such that tj = jh for j = 0, 1, 2, . . .

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Let wij denote an approximation to xi (tj) for each j = 0, 1, 2, . . . and i = 1, 2. For the initial conditions, set w1,0 = x0 and w2,0 = x 0. Obtain the approximation wij + 1, given all the values of the previous steps wij, as [31.1] 1 wi,j + 1 = wi,j + (k1,i + 2k2,i + 2k3,i + k4,i) i = 1, 2 (31.57) 6 where k1,i = hFi(tj + w1,j, w2,j) k2,i = hFi tj + k3,i = hFi tj + h 1 1 , w1,j + k1,1, w2i,j + k1,2 2 2 2 1 h 1 , w1,j + k2,1, w2,j + k2,2 2 2 2 i = 1, 2

(31.58)

For normal RS-232, MAX3100 would interface with the RS-232 line through an inverting RS-232 driver chip) Here is a simple getting-started demo of some of the main commands required to use the MAX3100 The demo first configures the MAX3100 for 2400 baud using the IrDA timing at the TX and RX pins It then transmits the quick brown fox jumps over the lazy dog plus a control/line feed (CRLF) Then it goes into a loop to receive data from the IrDA port and print it on the debug screen If the pushbutton on the above circuit is pressed, the program goes back and transmits the fox and lazy dog phrase again, so long as the pushbutton is down The RTS line is made high to turn on the red LED when the MAX3100 is transmitting You can readily change the output text to reflect your application.

Summary

k4,i = hFi(tj + h, w1,i + k3,1, w2, i + k3,2 )

Note that k1,1 and k1,2 must be computed before we can obtain k2,1. Example 1. Obtain the response of a generator rotor to a short-circuit disturbance given in Fig. 31.17. The generator shaft may be idealized as a single-degree-of-freedom system in torsion with the following values: 1 = 1737 cpm = 28.95(2 ) rad/s = 182 rad/s J = 8.5428 lb in s2 (25 kg m2) k = 7.329 106 lb in/rad (828 100 N m/rad) Solution Hence, J + k = f(t) = f(t) k = + J J k + f(t) = J J (31.59)

where f(t) is tabulated. Since 1 = 182 rad/s, the period = 2 /182 = 0.00345 s and the time interval h must be chosen to be around 0.005 s. Hence, tabulated values of f(t) must be available for t intervals of 0.005 s, or it has to be interpolated from Fig. 31.17.

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